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This circuit is used when delaying the standing-up of the
square wave signal. Also, in the case having to do
with the pulse of the input signal, it uses for the circuit as it changes
the output voltage gradually by the occurrence frequency of the pulse,
too. In the case, the resistor must be put in parallel with the capacitor
to miss the electric charge which was stored up at the
capacitor.
The use example : Door lock signal
making circuit and voltage change circuit of Car speed
detection device and so on.
The photograph above is the one of the
following condition.
| F |
: |
50Hz |
|
R |
: |
10K-ohm |
|
C |
: |
0.22΅F | |
 The electric charge begins to store up in capacitor(C) when the
voltage is applied to the input. The electric current which flows into
capacitor as the electric charge is stored up decreases. The electric current change which flows through the capacitor(C)
and the resistor (R) is demanded by the following formula.
i =
(V/R)e-(t/CR)
| i |
: |
The electric current which changes in the
time(A) |
| V |
: |
The applied voltage(V) |
| R |
: |
The resistance value(ohm) |
| C |
: |
The capacitor value(F) |
| e |
: |
The base of the natural
logarithm(2.71828) |
| t |
: |
The elapsed time after the charging
beginning(sec) |
| CR |
: |
The capacitive time constant (C x
R) |
The change of the voltage(Vc) which appears
in the both edges of the capacitor(C) becomes the following
formula.Vc =
V[1-e-(t/CR)]It is as follows when
showing the formula above by the graph.
The calculation of exponential can be
calculated with the Exp button of the electronic calculator application
(the function electronic calculator) to be equipped with the standard in
case of Windows95.
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